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Two point changes -q and +q are located at points (0, 0, -a) and (0, 0, +a) respectively. The electric potential of a point (0, b, 0), where b > a, is: |
Zero $\frac{1}{4 \pi \epsilon_{o}} \frac{q}{b^2}$ $\frac{1}{4 \pi \epsilon_{o}} \frac{2 qa}{\left(b^2-a^2\right)}$ $\frac{1}{4 \pi \epsilon_{o}} \frac{2 qa}{\left(b^2+a^2\right)}$ |
Zero |
The correct answer is Option (1) → Zero |
