Two point changes -q and +q are located at points (0, 0, -a) and (0, 0, +a) respectively. The electric potential of a point (0, b, 0), where b > a, is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → Zero
$V=V_1+V_2=\frac{k(-q)}{\sqrt{b^2+a^2}}+\frac{k(q)}{\sqrt{b^2+a^2}}$
$=0$