The order and degree of the differential equation of the family of curves $y=a(x+b)$ where a, b are arbitrary constants, are respectively.
Answer & explanation
Correct answer: option 2
The correct answer is option (2) → 2, 1
$y=a(x+b)$
No. of independent arbitrary constants = 2
order will be = 2
$\frac{dy}{dx}=ax$ ...(1)
differentiating again wrt x
$\frac{d^2y}{dx^2}=a$ from (1)
$\frac{d^2y}{dx^2}=\frac{1}{x}\frac{dy}{dx}$
order → 2, degree → 1