The angular velocity of a particle moving in a circle of radius 50 cm is increased in 5 min from 100 revolutions per minute to 400 revolutions per minute. Find the tangential acceleration of the particle.

$\frac{\pi}{60}$ m/s²

$\alpha \propto \frac{\omega_2 - \omega_1}{t}$

  = $\frac{400-100}{5}$ = 60 rev/min²

  = $\frac{60\times 2\pi}{60^2} = \frac{2 \pi}{60}$ rad/sec²

$a_t = \alpha r = \frac{2 \pi}{60} \frac{50}{100}$

  = $\frac{\pi}{60}$m/s²