The angular velocity of a particle moving in a circle of radius 50 cm is increased in 5 min from 100 revolutions per minute to 400 revolutions per minute. Find the tangential acceleration of the particle.
Answer & explanation
Correct answer: option 4
$\alpha \propto \frac{\omega_2 - \omega_1}{t}$
= $\frac{400-100}{5}$ = 60 rev/min2
= $\frac{60\times 2\pi}{60^2} = \frac{2 \pi}{60}$ rad/sec2
$a_t = \alpha r = \frac{2 \pi}{60} \frac{50}{100}$
= $\frac{\pi}{60}$m/s2