Minimum value of the function f(x)=sin(3x)+5 is equal to :

As minimum value of sin(3x) will be -1.

Therefore, the minimum value of sin(3x)+5 will be 4.

Given function: $f(x)=\sin(3x)+5$

Range of $\sin(3x)$ is $[-1,1]$

Therefore, range of $f(x)$ is $[-1+5,1+5]=[4,6]$

Minimum value = 4