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Minimum value of the function $f(x)=sin(3x)+5$ is equal to : |
0 5 4 6 |
4 |
As minimum value of sin(3x) will be -1. Therefore, the minimum value of sin(3x)+5 will be 4. Given function: $f(x)=\sin(3x)+5$ Range of $\sin(3x)$ is $[-1,1]$ Therefore, range of $f(x)$ is $[-1+5,1+5]=[4,6]$ Minimum value = 4 |
