If tan θ + cot θ = 12, then tan2 θ + cot2 θ is :
Answer & explanation
Correct answer: option 3
tan θ + cot θ = 12
on squaring both side
(tan θ + cot θ)2 = (12)2
tan2 θ + cot2 θ + 2 .tan θ .cot θ = 144
tan θ = \(\frac{1}{cot θ}\)
tan2 θ + cot2 θ + 2 = 144
tan2 θ + cot2 θ = 144-2 = 142