What is the product formed when \(Cl_2\) reacts with \(CS_2\) in presence of \(I_2\)?

\(CCl_4\)

The correct answer is option1. \(CCl_4\).

The reaction of chlorine with carbon disulfide in the presence of iodine is a free radical substitution reaction. The first step is the formation of a chlorine radical by homolytic cleavage of a chlorine molecule. The chlorine radical then reacts with carbon disulfide to form a dichlorocarbene radical. The dichlorocarbene radical then reacts with another chlorine molecule to form carbon tetrachloride.

The reaction can be summarized as follows:

Therefore, the product of the reaction is carbon tetrachloride \((CCl_4)\).