The number of neutrons released when ${ }_{92} U^{235}$ undergoes fission by absorbing ${ }_0 n^1$ and $\left({ }_{56} \mathrm{Ba}^{144}+{ }_{36} \mathrm{Kr}{ }^{89}\right)$ are formed, is

3

${ }_{92} U^{235}+{ }_0 n^1 \rightarrow {}_{92} U^{236}$ and 

${ }_{92} U^{236} \rightarrow {}_{56} \mathrm{Ba}^{144}+{ }_{36} \mathrm{Kr}+3_0 n^1+Q$