In ΔPQR, the side QR is extended to S such that RS = PR. If ∠QPS = 110° and ∠PRQ = 70°, then the value of ∠PQR is :
Answer & explanation
Correct answer: option 3
We have,
RS = PR
∠QPS = 110°
∠PRQ = 70°
∠PSR = ∠RPS = x [RS = PR]
Now, We know that,
∠PRQ = ∠PSR + ∠RPS
= 70° = 2x
= x = 35°
So, ∠QPR = 110° - 35° = 75°
∠PQR = 180° - (75° + 70°) = 180° - 145° = 35°