Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

The first junction on transistor consisting of two back to back P-N Junction was invented in 1951 by william schockley.Later New Bipolar Junction Transistor(BJT) were invented.Transistor has three doped regions forming two P-N junction between them.There are two types of transistors (i) P-N-P and (ii) N-P-N .Each transistor has three segments (i) Emitter (ii) Base (iii) Collector. The size and level of doping is different of all three segments.For connecting in the circuit three terminals of a transistors are available - emitter , base and collector and it can be connected in three configuration Common Emitter(CE) , Common Base(CB) and Common Collector(CC).the transistor can be used as a device application depending on configuration used,the biasing done to the segments and operate in the region namely cut off , Active and Saturation.It can work as an amplifier , a switch and an oscillator too.Based on transistor knowledge give answer.

The $\alpha$ and $\beta$ are the current gain in common base and common emitter configuration respectively in the transistor circuit then $\frac{\beta - \alpha}{\alpha \beta} $ is equal to :

Options:

Zero 

o.5 

1

2

Correct Answer:

1

Explanation:

$\text{ Relation between } \alpha \text{ and } \beta is $

$\frac{1}{\alpha} = \frac{1}{\beta} + 1$

$ \frac{1}{\alpha} - \frac{1}{\beta} = 1$

$\frac{\beta - \alpha}{\alpha \beta} = 1 $