CUET Preparation Today
CUET
-- Mathematics - Section A
Applications of Derivatives
The maximum value of the function $f(x)=-x^2+2 x-1$, is:
-1
0
1
2
The correct answer is Option (2) → 0
$f(x)=-x^2+2 x-1$
$y=-(x-1)^2$ so $y≤0$ always
$⇒y_{max}=0$ at $x=1$
