Match List-I with List-II.
| List-I | List-II | ||
| (A) | $(\hat{i}×\hat{j})+(\hat{j}×\hat{i})$ | (I) | 1 |
| (B) | $\hat{i}.\hat{i}+\hat{j}.\hat{j}+\hat{k}.\hat{k}$ | (II) | $\hat{k}-\hat{j}$ |
| (C) | $\hat{i}×(\hat{i}+\hat{j}+\hat{k})$ | (III) | $\vec{0}$ |
| (D) | $\hat{i}.(\hat{i}+\hat{j}+\hat{k})$ | (IV) | 3 |
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
(A) $(\hat{i}×\hat{j})+(\hat{j}×\hat{i})=0+0=\vec 0$ (III)
(B) $\hat{i}.\hat{i}+\hat{j}.\hat{j}+\hat{k}.\hat{k}=1+1+1=3$ (IV)
(C) $\hat{i}×(\hat{i}+\hat{j}+\hat{k})=\vec 0+\hat k-\hat j$ (II)
(D) $\hat{i}.(\hat{i}+\hat{j}+\hat{k})=1+0+0=1$ (I)