Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Vectors

Question:

Match List-I with List-II.

List-I List-II
(A) $(\hat{i}×\hat{j})+(\hat{j}×\hat{i})$ (I) 1
(B) $\hat{i}.\hat{i}+\hat{j}.\hat{j}+\hat{k}.\hat{k}$ (II) $\hat{k}-\hat{j}$
(C) $\hat{i}×(\hat{i}+\hat{j}+\hat{k})$ (III) $\vec{0}$
(D) $\hat{i}.(\hat{i}+\hat{j}+\hat{k})$ (IV) 3

Choose the correct answer from the options given below :

Options:

(A)-(II), (B)-(IV), (C)-(III), (D)-(I)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Correct Answer:

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

Explanation:

The correct answer is Option (2) → (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A) $(\hat{i}×\hat{j})+(\hat{j}×\hat{i})=0+0=\vec 0$ (III)

(B) $\hat{i}.\hat{i}+\hat{j}.\hat{j}+\hat{k}.\hat{k}=1+1+1=3$ (IV)

(C) $\hat{i}×(\hat{i}+\hat{j}+\hat{k})=\vec 0+\hat k-\hat j$ (II)

(D) $\hat{i}.(\hat{i}+\hat{j}+\hat{k})=1+0+0=1$ (I)