CUET Preparation Today
In the given figure, if QP || ST, then find the measure of $\angle PQR$.
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75° 72° 67° 39° |
72° |
BT is a straight line. So, ∠BSR = 180º - 2x QP is parallel to ST ∠PQB = ∠QBS = X QR is a straight line. So, ∠RBS = 180º - X In triangle BSR , 180º - 2x + 180º - X + 36º = 180º 3x = 216º x = 72º The correct answer is Option (2) → 72° |
