Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Question:

For the given values 8, 10, 12, 14, 16; the three-year moving averages are:

Options:

10, 12, 14

11, 13, 15

16, 14, 18

12, 14, 16

Correct Answer:

10, 12, 14

Explanation:

The correct answer is Option (1) → 10, 12, 14

Given data: 8, 10, 12, 14, 16

Three-year moving averages:

First 3-year average: $\frac{8+10+12}{3} = \frac{30}{3} = 10$

Second 3-year average: $\frac{10+12+14}{3} = \frac{36}{3} = 12$

Third 3-year average: $\frac{12+14+16}{3} = \frac{42}{3} = 14$