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Find the value of sec2θ - \(\frac{sin^2θ-2sin^4θ}{2cos^2θ-cos^2θ}\) is? |
1 2 -1 0 |
1 |
⇒ sec2θ - \(\frac{sin^2θ(1-2sin^2θ)}{cos^2θ(2cos^2θ-1)}\) We know cos2θ - sin2θ = 2cos2θ - 1 = 1 - 2sin2θ ⇒ sec2θ - tan2θ = 1 |
