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If $f(x)=\sqrt{x}, g(x)=2x-3, $ then domain of fog (x) is : |
$[\frac{3}{2}, ∞)$ $[\frac{1}{2}, ∞)$ $(\frac{3}{2}, ∞)$ $[\frac{5}{2}, ∞)$ |
$[\frac{3}{2}, ∞)$ |
The correct answer is option (1) → $[\frac{3}{2}, ∞)$ $fog(x)=f(g(x))$ $=f(2x-3)=\sqrt{2x-3}$ so $2x-3≥0$ $x≥\frac{3}{2}$ $⇒x∈[\frac{3}{2}, ∞)$ domain |
