Find the slope of the tangent or normal

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Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

Find the slope of the tangent or normal to given curves at the indicated point as instructed:

y=$ {x }^{ 3} $ at (1,1) : normal

Options:

x+3y-4=0

x+8y-7=0

x-y-4=0

x-y-1=0

Correct Answer:

x+3y-4=0

Explanation:

slope of normal = -1/ slope of tangent