CUET Preparation Today
CUET
-- Mathematics - Section A
Applications of Derivatives
Find the slope of the tangent or normal to given curves at the indicated point as instructed:
y=\( {x }^{ 3} \) at (1,1) : normal
x+3y-4=0
x+8y-7=0
x-y-4=0
x-y-1=0
slope of normal = -1/ slope of tangent
