A triangle is formed by folding a square card board of side 8 cm at its diagonal. What is the height of the triangle?
Answer & explanation
Correct answer: option 1
The triangle so formed will be isosceles as BC = DC = 8cm
and third side = diagonal BD = 8\(\sqrt {2}\) cm
DP = half of BD = 4\(\sqrt {2}\)
Height (CP) = \(\sqrt {CD^2 - DP^2}\)
= \(\sqrt {8^2 - (4\sqrt {2})^2}\)
= \(\sqrt {64 - 32}\)
= \(\sqrt {32}\) = 4\(\sqrt {2}\)