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Solution of the differential equation $\frac{dx}{x}+\frac{dy}{y}=0$, is |
$\frac{1}{x}+\frac{1}{y}=VC$ $log\, x \, log\, y = C$ $xy = C$ $x+y = C$ |
$xy = C$ |
The correct answer is option (3) : $xy = C$ We have, $\frac{1}{x}dx+\frac{1}{y}dy=0$ On integrating, we get $log\, x + log\, y = log\, C$ $⇒xy = C$ |
