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Home/Practice questions/Maths. Section B1
Maths. Section B1Matrices

If X+Y= […] and X-Y= […] , then Y is equal to

If \(X+Y=\begin{bmatrix}2 & 1\\3 & 5\end{bmatrix}\) and \(X-Y=\begin{bmatrix}0 & 3\\7 & 9\end{bmatrix}\), then Y is equal to

Answer & explanation+

Correct answer: option 3

The correct answer is Option (3) → \(\begin{bmatrix}1 & -1\\-2 & -2\end{bmatrix}\)

Subtracting the second equation from the first removes X:

    \( (X + Y) - (X - Y) = 2Y \)

    \( \displaystyle 2Y = \begin{bmatrix}2 - 0 & 1 - 3\\3 - 7 & 5 - 9\end{bmatrix} = \begin{bmatrix}2 & -2\\-4 & -4\end{bmatrix} \)

    \( \displaystyle Y = \begin{bmatrix}1 & -1\\-2 & -2\end{bmatrix} \)

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