CUET Preparation Today
When 1 mole of benzene is mixed with 1 mole of toluene then what is the correct statement about composition of vapour of solution? (Given: Vapour pressure of benzene = 12.8 kPa and Vapour pressure of toluene = 3.85 kPa) |
Equal amount of benzene and toluene as it forms an ideal solution Unequal amount of benzene and toluene as it forms a non ideal solution Higher percentage of benzene Higher percentage of toluene |
Higher percentage of benzene |
Higher percentage of benzene because its vapour pressure is high. mole fraction of benzene = \(\frac{1}{1+1}\) = \(\frac{1}{2}\) = 0.5 mole fraction of toluene = \(\frac{1}{1+1}\) = \(\frac{1}{2}\) = 0.5 p (benzene) = 12.8 x 0.5 = 6.4 kPa p (toluene) = 3.85 x 0.5 = 1.925 kPa
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