Approximate percentage increase in the volume of sphere if its radius…

The correct answer is Option (2) - 9%

r → radius, v → volume

$v=\frac{4}{3}πr^3$ so $\frac{dv}{dr}=4πr^2$

so $Δv=\frac{dv}{dr}×Δr$

$=4πr^2×\frac{3}{100}×r$

$=\frac{9}{100}×\frac{4}{3}πr^3=\frac{9}{100}×v$

or 9%