A pair of adjacent coils has a mutual inductance of 2.0 H. If the current in one coil changes from 0 to 25 A in 0.8 s, the change of flux linkage with the other coil is

50 Wb

The correct answer is Option (1) → 50 Wb

Mutual inductance relation: $M = \frac{\Delta \Phi}{\Delta I}$

Given: $M = 2.0 \,\text{H}, \;\Delta I = 25 \,\text{A}, \;\Delta t = 0.8 \,\text{s}$

$\Delta \Phi = M \cdot \Delta I = 2.0 \times 25 = 50 \,\text{Wb-turn}$

Change of flux linkage = 50 Wb-turn