CUET Preparation Today
A random variable X has the following probability distribution:
The value of m is: |
10 $\frac{1}{10}$ -1 and $\frac{1}{10}$ $\frac{1}{20}$ |
$\frac{1}{10}$ |
The correct answer is Option (2) → $\frac{1}{10}$ $∑P(X)=1$ $0+m+2m+2m+3m+m^2+2m^2+7m^2+m=1$ $10m^2+9m=1$ $m=\frac{1}{10}$ |
