A random variable X has the following probability distribution:
|
X |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
|
P(X) |
0 |
m |
2m |
2m |
3m |
$m^2$ |
$2m^2$ |
$7m^2 +m$ |
The value of m is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{1}{10}$
$∑P(X)=1$
$0+m+2m+2m+3m+m^2+2m^2+7m^2+m=1$
$10m^2+9m=1$
$m=\frac{1}{10}$