Two resistances of 100Ω and 200Ω are connected in series across a 20 V battery as shown in figure below. The reading in a 200Ω voltmeter connected across the 200Ω resistance is _________.

Fill in the blank with the correct answer from the options given below:

10 V

Effective resistance in the circuit is $ R = 100+\frac{200\times 200}{200+200} = 200 \Omega$

$ I = \frac{20}{200} = 0.1A$

Current through 200 $\Omega$ is 0.05 A.

Voltage across 200$\Omega$ is $ V = 200\times 0.05 V = 10V$

The correct answer is Option (3) → 10 V