Practicing Success
Practicing Success
CUET Preparation Today
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$α=\tan^{-1}(\frac{30}{30\sqrt{3}})=30°$ $β=\tan^{-1}(\frac{30}{10\sqrt{3}})=60°$ so $∠ABC=180°-(α+β)$ $=180°-90°$ $=90°=\frac{\pi}{2}$ |
