CUET Preparation Today
CUET
-- Mathematics - Section B1
Inverse Trigonometric Functions
$α=\tan^{-1}(\frac{30}{30\sqrt{3}})=30°$
$β=\tan^{-1}(\frac{30}{10\sqrt{3}})=60°$
so $∠ABC=180°-(α+β)$
$=180°-90°$
$=90°=\frac{\pi}{2}$
