The Bar graph given below presents the marks (out of 100) obtained by 10 students in a subject.
The marks obtained by S5 is how much percent more than the average marks of the students (correct to two decimal)?
Answer & explanation
Correct answer: option 1
Average marks = \(\frac{92 + 88 + 87 + 94 + 99 + 97 + 86 + 85 + 100 + 91 }{10}\)
= \(\frac{919}{10}\)
= 91.9
Marks obtained by S5 = 99
Required percentage = \(\frac{99 - 91.9 }{91.9}\) × 100
= \(\frac{7.1 }{91.9}\) × 100
= 7.73%