The Bar graph given below presents the marks (out of 100) obtained by 10 students in a subject.

The marks obtained by S5 is how much percent more than the average marks of the students (correct to two decimal)?

7.73%

Average marks = \(\frac{92 + 88 + 87 + 94 + 99 + 97 + 86 + 85 + 100 + 91 }{10}\)

= \(\frac{919}{10}\)

= 91.9

Marks obtained by S5 = 99

Required percentage = \(\frac{99 - 91.9 }{91.9}\) × 100

= \(\frac{7.1 }{91.9}\) × 100

= 7.73%