Five men can complete a work in 20 days. Ten women can complete the same work in 15 days. Two men and six women started working together. After 5 days, three women left the work and a new man joined the work. The group continued working together till the end of the work. In how many days will they be able to do the remaining work?
Answer & explanation
Correct answer: option 2
As given,
⇒ 5M x 20 = 10W x 15 where, M = Men , W = Women.
⇒ 2M = 3W
⇒ M : W = 3 : 2 (Efficiency)
⇒ Total work = 5M x 20 = 5(3) x 20 = 300 units. ..(Efficiency × Days = Total work)
Now, (2M + 6W) x 5 = (6 + 12) x 5 = 90 units.
⇒ Remaining work = 300 - 90 = 210 units.
⇒ Now, One more man joined and 3 women left = 3(3) + 3(2) = 15 (Efficiency)
⇒ Now this group will complete remaining work in = \(\frac{210}{15}\) = 14 days.