A basket contain 4 red, 5 blue and 3 green marbles. If 2 marbles are drawn at random what is the probability that both are red ?

$\frac{1}{11}$

Total number 4 of marbles = 4 + 5 + 3 = 11

Probability of drawing 2 marbles = ${^12C_{2}}$

= \(\frac{ 12! }{2! ( 10)!}\)

= 66

Number of red marbles = 4

Probability of drawing 2 marbles = ${^4C_{2}}$

= \(\frac{ 4! }{2! ( 2)!}\)

= 6

probability that both are red marbles = \(\frac{ 6 }{66}\)

= \(\frac{ 1 }{11}\)

The correct answer is option (3) : $\frac{1}{11}$