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A current of 2 ampere is flowing in a coil of radius 50 cm and number of turns 20. The magnetic moment of the coil will be- |
$3.14 A-m^2$ $31.4 A-m^2$ $314 A-m^2$ $0.314 A-m^2$ |
$31.4 A-m^2$ |
$ M = NI\pi R^2 = 20\times 2 \times 3.14 \times 0.25 = 31.4 A-m^2$ |
