A current of 2 ampere is flowing in a coil of radius 50 cm and number of turns 20. The magnetic moment of the coil will be-
Answer & explanation
Correct answer: option 2
$ M = NI\pi R^2 = 20\times 2 \times 3.14 \times 0.25 = 31.4 A-m^2$
A current of 2 ampere is flowing in a coil of radius 50 cm and number of turns 20. The magnetic moment of the coil will be-
Correct answer: option 2
$ M = NI\pi R^2 = 20\times 2 \times 3.14 \times 0.25 = 31.4 A-m^2$