If the time period of a drop of liquid of density d, radius r, vibrating under surface tension s is given by the formula t = (da rb sc)1/2 and if a = 1, c = -1, then b is :
Answer & explanation
Correct answer: option 3
T = (ML-3)a/2 Lb/2 (ML0T-2)c/2
M0L0T = Ma/2+c/2 L-3a/2+b/2 T-c
$\frac{-3a}{2}+\frac{b}{2} = 0$
-3a + b = 0
b = 3a
b = 3 × 1
b = 3