The volume of the water in two tanks, A and B,is in the ratio of 6 : 5. The volume of water in tank A is increased by 30%. By what percentage should the volume of water in tank B be increased so that both the tanks have the same volume of water?

56%

volume of     tank A    :     tank B

                       6        :        5

Let volume of tank A = 60 & Volume of tank B = 50

Increased volume of tank A = 60 +  \(\frac{3}{10}\) × 60 = 78

( As after increment volume of both tank will be same )

So , Percentage increment in volume of tank B =  \(\frac{78 - 50}{50}\) × 100

=  \(\frac{28}{50}\) × 100

= 56%