The volume of the water in two tanks, A and B,is in the ratio of 6 : 5. The volume of water in tank A is increased by 30%. By what percentage should the volume of water in tank B be increased so that both the tanks have the same volume of water?
Answer & explanation
Correct answer: option 1
volume of tank A : tank B
6 : 5
Let volume of tank A = 60 & Volume of tank B = 50
Increased volume of tank A = 60 + \(\frac{3}{10}\) × 60 = 78
( As after increment volume of both tank will be same )
So , Percentage increment in volume of tank B = \(\frac{78 - 50}{50}\) × 100
= \(\frac{28}{50}\) × 100
= 56%