A 80Ω resistor is connected to a 240 V, 50 Hz ac supply. The net power consumed over a full cycle is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 720 W
For a pure resistor in AC circuit, the net power over a full cycle is given by:
$P = V_\text{rms}^2 / R$
Given: $R = 80\ \Omega$, $V_\text{rms} = 240\ \text{V}$
Substitute values:
$P = \frac{(240)^2}{80} = \frac{57600}{80} = 720\ \text{W}$
Final Answer: $P = 720\ \text{W}$