Two coherent light beams of intensities I and 4 I are superimposed. The maximum and minimum possible intensities in the resulting pattern are: |
5 I and 3 I 5 I and I 9 I and I 9 I and 3 I |
9 I and I |
The correct answer is Option (3) → 9 I and I Maximum intensity ($I_{max}$) is, $I_{max}=\left(\sqrt{I_1}+\sqrt{I_2}\right)^2$ $=\left(\sqrt{I}+\sqrt{4I}\right)^2=9I$ Maximum intensity ($I_{max}$) is, $I_{max}=\left(\sqrt{I_1}-\sqrt{I_2}\right)^2$ $=\left(\sqrt{I}-\sqrt{4I}\right)^2=I$ |