Practicing Success
Find the values of x for which matrix $\begin{bmatrix}3&-1+x&2\\3&-1&x+2\\x+3&-1&2\end{bmatrix}$ is singular. |
0 -4 0, -4 None of these |
0, -4 |
Given matrix is singular $∴\begin{bmatrix}3&-1+x&2\\3&-1&x+2\\x+3&-1&2\end{bmatrix}=0$ $⇒\begin{bmatrix}0&x&-x\\3&-1&x+2\\x+3&-1&2\end{bmatrix}=0$ $[R_1→R_1-R_2]$ $⇒\begin{bmatrix}0&x&-x\\-x&0&x\\x+3&-1&2\end{bmatrix}=0$ $[R_2→ R_2-R_3]$ $⇒\begin{bmatrix}0&x&0\\-x&0&x\\x+3&-1&1\end{bmatrix}=0$ $[C_3 → C_3 + C_2]$ $⇒-x [(-x)-x(x+3)] = 0$ $⇒x(x^2 + 4x) = 0$ $⇒x = 0, -4$ |