There are two numbers such that the first number is three times of the second number. If the average of these two numbers is 72, then what is the first number?
Answer & explanation
Correct answer: option 1
Let second number = a
Then 1st number = 3a
ATQ ,
a + 3a = 2 × 72 = 144
4a = 144
a = 36
First number = 3a = 3 × 36 = 108