Let $ f(x) = cos 2 \pi x + x -[x]$ ([.] denotes the greatest integer function). Then the number of points in [0, 10], at which f (x) assumes its local maximum value, is |
10 12 15 8
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10 |
The correct answer is option (1) : 10 We have, $f(x) cos 2\pi x + x - [x]\, ∀\, x \in [0, 10]$ $⇒f'(x) = -2 \pi sin 2 \pi x + 1 \, ∀ x \in \underset{k = 0}{\overset{9}{∪}}(k, k+1)$ $∴f'(x) = 0 ⇒sin 2 \pi x =\frac{1}{2\pi }$ Clearly, this equation has two solutions in each of the sub-intervals $(k, k+1)$, where k = 0, 1, 2, ..., 0. Since points of maxima and minima occur alternately. Therefore, out of 20 points, there are 10 points of local maxima and 10 points of local minima. |