CUET Preparation Today
The principal value of $\cot ^{-1}\left(\frac{-1}{\sqrt{3}}\right)$ is: |
$-\frac{\pi}{3}$ $\frac{\pi}{3}$ $\frac{2 \pi}{3}$ $\frac{5 \pi}{3}$ |
$\frac{2 \pi}{3}$ |
The correct answer is Option (3) → $\frac{2 \pi}{3}$ $\cot^{-1}\left(\frac{-1}{\sqrt{3}}\right)=π-\cot^{-1}\left(\frac{-1}{\sqrt{3}}\right)$ $=π-\frac{π}{3}=\frac{2π}{3}$
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