Practicing Success
Practicing Success
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A particle of mass m moves in the XY plane with a velocity v along the straight line AB. If the angular momentum of the particle with respect to origin O is LA when it is at A and LB when it is at B, then :
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LA = LB the relationship between LA and LB depends upon the slope of the line AB LA < LB LA > LB . |
LA = LB |
Angular momentum = Linear momentum × distance of line of action of linear momentum about the origin.
LA = PA × d, LB = PB × d As linear momenta are equal, therefore, LA = LB . |
