An ac source has a frequency of 60 Hz. The time taken for the voltage to change from peak value to zero is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{1}{240}s$
The time period (T) is given by -
$T=\frac{1}{f}=\frac{1}{60}$
∴ Time taken, $t=\frac{T}{4}=\frac{\frac{1}{60}}{4}=\frac{1}{240}s$