CUET Preparation Today
An ac source has a frequency of 60 Hz. The time taken for the voltage to change from peak value to zero is: |
$\frac{1}{240}s$ $\frac{1}{120}s$ $\frac{1}{60}s$ $\frac{1}{180}s$ |
$\frac{1}{240}s$ |
The correct answer is Option (1) → $\frac{1}{240}s$ The time period (T) is given by - $T=\frac{1}{f}=\frac{1}{60}$ ∴ Time taken, $t=\frac{T}{4}=\frac{\frac{1}{60}}{4}=\frac{1}{240}s$ |
