Read the passage carefully and answer the Questions.

Haloalkanes undergo nucelophilic substitution reactions owing to the polarity of C-X bond. The nucleophile reacts with the haloalkane on the carbon possessing a partial positive charge holding the halogen atom. The halogen atom X is replaced by a nucleophile. Depending on the kinetics and mode of bond breaking, the mechanism can be either $S_N1$ or $S_N2$ reaction. The rate of $S_N1$ reaction is governed by the stability of carbocation and in $S_N2$ reaction, the rate of reaction is governed by steric factor. Chirality is the main factor in both $S_N1$ and $S_N2$. In $S_N1$ reaction, the chirality of alkyl halide is accompanied by racemization of the product, while in $S_N2$ reaction, the product is characterized by inversion of configuration. The structure of alkyl halide and the nature of the solvent also governs the mechanism of the substitution.

Hydrolysis of 2-Chlorobutane will result in formation of

2-Butanol

The correct answer is Option (4) → 2-Butanol **

Hydrolysis of 2-chlorobutane occurs through the SN1 mechanism because it forms a secondary carbocation.

SN1 reactions lead to racemization (mix of both enantiomers), since the nucleophile can attack from either side.

Therefore, the product will be a racemic mixture:

✅ (±) 2-Butanol