CUET Preparation Today
The number of all possible matrices of order 2 × 3 with each entry 0 or 1 is |
32 64 128 512 |
64 |
The correct answer is Option (2) - 64 No. of cells = 2 × 3 = 6 No of possibilities for each cell = 2 No of matrices = No of unique cell combination $=2^6=64$ |
