Total cost price of two watches is Rs.6000 and selling price of each is equal. 1st is sold at 15% loss and 2nd is sold at 19% profit. Find the cost price of watch which is sold at 15% loss.
Answer & explanation
Correct answer: option 3
C.P. : S.P.
1st : 20 : 17 ........(i) [15% = \(\frac{3}{20}\)]
2nd: 100 : 119 [19% = \(\frac{19}{100}\)]
ATQ, (S.P. is same), therefore multiple (i) by 7
C.P. : S.P.
1st : 140 : 119
2nd: 100 : 119
240 (total C.P.)
⇒ 240R = 6000 (given)
⇒ 1R = 25
Hence,
C.P. of 1st article = 140R = 140 × 25 = Rs.3500/-