If $\frac{1}{x^2+a^2} = x^2 - a^2$, then the value of x is:
Answer & explanation
Correct answer: option 4
If $\frac{1}{x^2+a^2} = x^2 - a^2$
1 = ($x^2 - a^2$) ($x^2 + a^2$)
we know = a4 – b4 = ($a^2 - b^2$) ($a^2 + b^2$)
x4 – a4 = ($x^2 - a^2$) ($x^2 + a^2$)
x4 – a4 = 1
x4 = 1 + a4
x = $(a^4+1)^{1/4}$