Practicing Success
Practicing Success
CUET Preparation Today
If $\frac{1}{x^2+a^2} = x^2 - a^2$, then the value of x is: |
$(1-a^4)^{1/4}$ a $(a^4-1)^{1/4}$ $(a^4+1)^{1/4}$ |
$(a^4+1)^{1/4}$ |
If $\frac{1}{x^2+a^2} = x^2 - a^2$ 1 = ($x^2 - a^2$) ($x^2 + a^2$) we know = a4 – b4 = ($a^2 - b^2$) ($a^2 + b^2$) x4 – a4 = ($x^2 - a^2$) ($x^2 + a^2$) x4 – a4 = 1 x4 = 1 + a4 x = $(a^4+1)^{1/4}$ |
