CUET Preparation Today
The value of current $I_1$, in the circuit diagram given below is:
|
$\frac{1}{3}A$ 1 A 2 A $\frac{2}{3}A$ |
$\frac{2}{3}A$ |
The correct answer is Option (4) → $\frac{2}{3}A$ The total resistance ($R_{total}$) in circuit - $R_{total}=\frac{2}{3}+\frac{10}{3}=\frac{12}{3}=4Ω$ $I=\frac{V}{R}=\frac{4}{4}=1A$ [By Ohm's law] ∴ Current in $I_1=1×\frac{2}{3}=\frac{2}{3}A$ |
