The value of current I_1, in the circuit diagram given below is:

The correct answer is Option (4) → $\frac{2}{3}A$

The total resistance ($R_{total}$) in circuit -

$R_{total}=\frac{2}{3}+\frac{10}{3}=\frac{12}{3}=4Ω$

$I=\frac{V}{R}=\frac{4}{4}=1A$ [By Ohm's law]

∴ Current in $I_1=1×\frac{2}{3}=\frac{2}{3}A$