Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Question:

If x:y be the ratio of two whole numbers and z be their HCF then the LCM of these two numbers is:

Options:

\(\frac{xy}{z}\)

\(\frac{xz}{y}\)

xyz

\(\frac{1}{xyz}\)

Correct Answer:

xyz

Explanation:

Ratio of the numbers = x : y

HCF of the numbers  =  z

So, z is the common factor of the numbers

Then, First number  =  xz

Second Number  =  yz

Now,

First Number  ×  Second Number  = HCF  × LCM of the numbers

xz × yz = z × LCM

LCM = xyz