The volume of a solid right circular cylinder is 5236 cm$^3$, and its height is 34 cm. What is its curved surface area (in cm$^2$)? (Take $\pi = \frac{22}{7}$)

1496

We know that,

Volume of cylinder = πr²h

Curved surface area of cylinder = 2πrh

We have,

The volume of cylinder = 5236 cm³.

Height of the cylinder = 34 cm

According to the question,

= πr²h = 5236

= \(\frac{22}{7}\) × r² × 34 = 5236

= r² = \(\frac{5236×7}{22×34}\)

= r = \(\sqrt {49}\) = 7 cm

Now, Curved surface area of cylinder = = 2 × \(\frac{22}{7}\) × 7 × 34 = 1496 cm²