The volume of a solid right circular cylinder is 5236 cm$^3$, and its height is 34 cm. What is its curved surface area (in cm$^2$)? (Take $\pi = \frac{22}{7}$)
Answer & explanation
Correct answer: option 4
We know that,
Volume of cylinder = πr2h
Curved surface area of cylinder = 2πrh
We have,
The volume of cylinder = 5236 cm3.
Height of the cylinder = 34 cm
According to the question,
= πr2h = 5236
= \(\frac{22}{7}\) × r2 × 34 = 5236
= r2 = \(\frac{5236×7}{22×34}\)
= r = \(\sqrt {49}\) = 7 cm
Now, Curved surface area of cylinder = = 2 × \(\frac{22}{7}\) × 7 × 34 = 1496 cm2