Practicing Success
Practicing Success
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If $x^4 +\frac{1}{x^4}= 16$, then what is the value of $x^2 +\frac{1}{x^2}$ ? |
$4\sqrt{2}$ $3\sqrt{2}$ $2\sqrt{2}$ $5\sqrt{2}$ |
$3\sqrt{2}$ |
If $x^4 +\frac{1}{x^4}= 16 Then what is the value of $x^2 +\frac{1}{x^2}$ If x4 + \(\frac{1}{x^4}\) = a then x2 + \(\frac{1}{x^2}\) = \(\sqrt {a + 2}\) x2 + \(\frac{1}{x^2}\) = \(\sqrt {16 + 2}\) = $3\sqrt{2}$ |
