If x^4 +1/(x^4)= 16, then what is the value of x^2 +1/(x^2) ?

If $x^4 +\frac{1}{x^4}= 16

Then what is the value of $x^2 +\frac{1}{x^2}$

If x⁴ + \(\frac{1}{x^4}\) = a

then x² + \(\frac{1}{x^2}\) = \(\sqrt {a + 2}\)

x² + \(\frac{1}{x^2}\) = \(\sqrt {16 + 2}\) = $3\sqrt{2}$