The average of 10 consecutive integers is 33/2. What is the average o…

Let the integers be x, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9

Sum of these integers = 10x + 45 = \(\frac{33}{2}\) x 10

                                 ⇒ 10x + 45 = 165

                                 ⇒ x = 12

Average of first three integers =\(\frac{ 12 + 13 + 14}{3}\) = 13