The average of 10 consecutive integers is 33/2. What is the average of first three integers ?

12 13 15 11

13

Let the integers be x, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9 Sum of these integers = 10x + 45 = \(\frac{33}{2}\) x 10                                  ⇒ 10x + 45 = 165                                  ⇒ x = 12 Average of first three integers =\(\frac{ 12 + 13 + 14}{3}\) = 13