Find at what time between 8 to 9 o'clock will the hands of a clock be in the same straight line but not together.

8 : 10\(\frac{10}{11}\)

Use this formula for this type of question: (5n - 30)× \(\frac{12}{11}\),

where n is the minimum value of time which is given in the question.

Here, n = 8

Therefore, The hand will be in straight line but not together after = (5 × 8 - 30) × \(\frac{12}{11}\) = 10 × \(\frac{12}{11}\) = × \(\frac{120}{11}\) = 10\(\frac{10}{11}\) min

The hand will be in straight line but not together at = 8 : 10\(\frac{10}{11}\)