Find the distance between the points (2, -4) and (1, 2).

The correct answer is Option (4) → \(\sqrt{37}\) units

By the distance formula, the distance between \((x_1,y_1)\) and \((x_2,y_2)\) is \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\): the two differences are the legs of a right triangle, and the distance is its hypotenuse.

• Difference of the x-coordinates: \(1-2=-1\)

• Difference of the y-coordinates: \(2-(-4)=6\)

• Distance \(=\sqrt{(-1)^2+6^2}=\sqrt{1+36}=\sqrt{37}\) units